Question

A tram moves with a velocity u. A particle moving horizontally with a speed v enters through corner B perpendicular to u. This particle strikes the diagonally opposite corner A. If the dimensions of tram are 16 × 2.4 × 3.2 m³ the value of u is

• A. 3 ms^-1
• B. 20ms^-1
• C. 15 ms^-1
• D. 30ms^-1

Answer 1

Answer: (B)

20ms^-1

Answer 2

Considering the vertical motion,

3.2 = $\frac{1}{2}$ × 10 × t² i.e., t = 0.8 s

The particle covers 2.4 m due to velocity component v and it covers 16 m due to velocity u in 0.8 s

∴ u = 16/0.8 = 20 ms^-1