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Question

Physics Question on speed and velocity

A train travels east towards Hubli at 80km/hr.80\, km/hr. A man on the train runs from the front of the train toward the rear of the train at 10km/hr10\, km/hr with respect to train. As he runs, he carries a plate of fruit with him. He notices a giant spider on the plate and throws the plate away from him (toward the rear of the train) at 20km/hr20\, km/hr with respect to him. Just after that instant, the startled spider jumps towards the man at 5km/hr5\, km/hr with respect to plate. The instant after the spider jumps toward the man, how fast is the spider approaching Hubli?

A

45km/hr

B

115 km/hr

C

55 km/hr

D

95 km/hr

Answer

55 km/hr

Explanation

Solution

Given, velocity of train w.r.t. the earth, VTE=80km/h(i)V_{T\to E} =80\, km/h \ldots\left(i\right) Velocity of the man w.r.t. the train, VMT=10km/h(ii)V_{M\to T}=-10\, km/h \ldots\left(ii\right) Velocity of the plate w.r.t. the man, VPM=20km/h(iii)V_{P\to M} =- 20\, km/h \ldots\left(iii\right) Velocity of the spider w.r.t. the plate, VSP=5km/h(iv)V_{S\to P} = 5km/h \dots\left(iv\right) From Eqs. (i), (ii), (iii) and (iv), we get \therefore The velocity of the spider w.r.t. the earth, VSE=VSP+VPM+VMT+VTEV_{S\to E}=V_{S\to P}+V_{P\to M} +V_{M \to T}+V_{T\to E} =52010+80=5-20-10+80 =55km/h= 55km/h (towards Hubli)