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Question

Physics Question on Waves

A train standing at the outer signal of a railway station blows a whistle of frequency 400Hz400 \,Hz in still air. The train begins to move with a speed of 30ms130\, m\, s^{-1} towards the platform. The frequency of the sound heard by an observer standing on the platform is (Speed of sound in air = 330ms1)330\,m \, s^{-1})

A

420Hz420\, Hz

B

430Hz430\, Hz

C

440Hz440 \, Hz

D

450Hz450 \, Hz

Answer

440Hz440 \, Hz

Explanation

Solution

Here, Frequency of source, υ=400Hz\upsilon=400\, Hz Speed of sound, v=330ms1v = 330 \, m \, s^{-1} Speed of source (i.e. train), υs=30ms1\upsilon_{s}=30\, m\,s^{-1} As the source is moving towards stationary observer υ=υvvvs=(400Hz)×(330ms1)330ms130ms1\therefore \upsilon' =\frac{\upsilon v}{v-v_{s}}=\frac{\left(400\,Hz\right)\times\left(330\,m\,s^{-1}\right)}{330\,m\,s^{-1}-30\,m\,s^{-1}} =440Hz=440\,Hz