Question
Physics Question on work, energy and power
A train of weight 107 N is running on a level track with uniform speed of 36kmh−1. The frictional force is 0.5 kg f per quintal. If g=10ms−2, power of engine is
A
500 kW
B
50 kW
C
5 kW
D
0.5 kW
Answer
500 kW
Explanation
Solution
Weight of train = 107N=106kgf
Frictional force, F=1000.5×106=5000kgf
F=50000N
v=36kmh−1=10ms−1
P=F×v=50000×10=5×105W=500kW