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Question

Physics Question on work, energy and power

A train of weight 107 N10^7\ N is running on a level track with uniform speed of 36kmh1{36\, km\, h^{-1}}. The frictional force is 0.5 kg f per quintal. If g=10ms2g ={ 10 \, m \, s^{-2}}, power of engine is

A

500 kW

B

50 kW

C

5 kW

D

0.5 kW

Answer

500 kW

Explanation

Solution

Weight of train = 107N=106kgf{10^7 \, N = 10^6\, kg\, f}
Frictional force, F=0.5100×106=5000kgfF = \frac{0.5}{100} \times 10^6 = 5000 \, { kg \, f}
F=50000NF = 50000 \, N
v=36kmh1=10ms1v ={ 36 km \, h^{-1} = 10 \, m \, s^{-1}}
P=F×v=50000×10=5×105W=500kWP = F \times v = {50000 \times 10 = 5 \times 10^5 \, W = 500 \, kW }