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Question: A train leaves New Delhi railway station at \( 9am \) and reaches Jaipur, which is at a distance of ...

A train leaves New Delhi railway station at 9am9am and reaches Jaipur, which is at a distance of 260km260km at 12:45pm12:45pm the train reaches Alwar at a distance 150km150km from Delhi at 11:30am11:30am and stop there for 15min15\min . What is the average speed of the train between Alwar and Jaipur?

Explanation

Solution

Use the relation between speed, distance, and time. Find the distance between Alwar and Jaipur from the question and time taken by the train to reach from Alwar to Jaipur. We will get the required average speed.
s=dts = \dfrac{d}{t}
Where ss is the speed, dd is the distance, tt is the time.

Complete answer:
A train leaves New Delhi railway station at 9am9am
Reaches Jaipur at 12:45pm12:45pm
Total time to reach Jaipur from New Delhi 3hours45min3hours45\min that is 180+45min=225min180 + 45\min = 225\min
The same train reaches Alwar at 11:30am11:30am
Total time to reach Alwar from New Delhi 2hours30min2hours30\min that is 120+30min=150min120 + 30\min = 150\min
It is given that train stops of 15min15\min at Alwar.
Therefore train starts from Alwar to Jaipur after 165min165\min
Total distance from Alwar to Jaipur will be the distance from New Delhi to Jaipur minus distance from New Delhi to Alwar 260km150km=110km260km - 150km = 110km
Total time is taken by the train to reach from Alwar to Jaipur 225min165min=60min225\min - 165\min = 60\min
We know 60min=1hour60\min = 1hour
So s=dts = \dfrac{d}{t}
Where ss is the speed, dd is the distance, tt is the time
s=1101(hour)\Rightarrow s = \dfrac{{110}}{{1(hour)}}
Hence, the average speed of the train between Alwar and Jaipur is 110kmhour110\dfrac{{km}}{{hour}} .

Note:
The units of all the physical quantities should be in the same system. For example: if the distance is given in kilometres and time is given in hours, then speed will be calculated in kilometres per hour initially. Then, we convert the unit of speed using the conversion rate. To convert from kmhr\dfrac{{km}}{{hr}} to ms\dfrac{m}{\operatorname{s} } , we multiply by 518\dfrac{5}{{18}} .