Question
Question: A train is travelling at a speed of 90kmph. Brakes are applied so as to produce a uniform accelerati...
A train is travelling at a speed of 90kmph. Brakes are applied so as to produce a uniform acceleration of −0.5ms−2 . Find how far the train will go before it comes to rest.
(A). 625m
(B). 4050m
(C). 8100m
(D). 1250m
Solution
As acceleration is constant, using equations of motion, we can calculate the distance covered by substituting the corresponding values. Convert the units as required. Negative acceleration means that the train is coming to a rest, this means that the final velocity will be zero.
Formula used:
v2=u2+2as
Complete step by step solution:
The initial speed of the train is 90kmhr−1 converting it into SI system, we get,
1×3600s90×1000m=25ms−1
As the train is moving with constant deceleration, the distance covered by it can be calculated using the formula-
v2=u2+2as
Here,
v is the final velocity
u is the initial velocity
a is acceleration
s is the distance covered
As the train is coming to a rest,
v=0ms−1
Substituting values in the above equation, we get,