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Question

Physics Question on Motion in a straight line

A train is moving slowly on a straight track with a constant speed of 2ms12\, ms^{-1} passenger in that train starts walking at a steady speed of 2ms12\, ms^{-1} to the back of the train in the opposite direction of the motion of the train. So to an observer standing on the platform directly in front of that passenger, the velocity of the passenger appears to be

A

2ms12 \,ms^{-1} in the opposite direction of the train.

B

zero

C

4ms14\, ms^{-1}

D

2ms12 \,ms^{-1}

Answer

zero

Explanation

Solution

Relative velocity of passenger w.r.t. train
=vpassenger vtrain =22=0=v_{\text {passenger }}-v_{\text {train }}=2-2=0
\therefore Relative velocity of the passenger w.r.t. the observer is zero.