Question

A trader sells 10 litres of a mixture of paints A and B, where the amount of B in the mixture does not exceed that of A.The cost of paint A per litre is Rs. 8 more than that of paint B. If the trader sells the entire mixture for Rs. 264 and makes a profit of 10%, then the highest possible cost of paint B, in Rs. per litre, is

• A. 26
• B. 16
• C. 20
• D. 22

Answer 1

Answer: (C)

20

Answer 2

The correct answer is (C):
Let the quantities of the paints A and B in the mixture sold be a litres and b litres respectively.
Value at which the entire mixture is sold=264 Profit percent made=10%
Value at which the entire mixture is bought = 264×100/110 = 240
Price at which the entire mixture is bought=24 per litre Let the cost of B be x per litre.
Cost of A=(x+8)per litre
(x+8)a+xb/10 = 24
Maximum cost of B will occur when a is minimum. b<=a. So, minimum a is 5.
Corresponding b is 5.
Then (x+8)(5)+x(5)=240 x=20