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Question

Mathematics Question on Surface Area of a Combination of Solids

A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius. The total height of the toy is 15.5 cm. Find the total surface area of the toy.[Use π=227\pi=\frac{22 }{7} ]

Answer

A toy is in the form of a cone of radius 3.5 cm mounted on a hemisphere of same radius

It can be observed that the radius of the conical part and the hemispherical part is same (i.e., 3.5 cm).
Height of hemispherical part = Radius (r) = 3.5 = 72\frac{7}{2} cm
Height of conical part (h) = 15.5 −3.5 = 12 cm

Slant height of cone
=AB=l=r2+h2=AB=l=\sqrt{r^2+h^2}
=(72)2+(12)2=494+144=\sqrt{(\frac{7}{2})^{2}+(12)^2}=\sqrt{\frac{49}{4}+144}
=6254=252=12.5=\sqrt{\frac{625}{4}}=\frac{25}{2} = 12.5 cm

Total surface area of toy = CSA of conical part + CSA of hemispherical part
=πrl+2πr2= \pi rl+2\pi r^2

=(227)×(72)×(252)+2×(227)×(72)2=(\frac{22}{7})×(\frac{7}{2})×(\frac{25}{2})+2×(\frac{22}{7})×(\frac{7}{2})^2

=(2752)+77= (\frac{275}{2})+77 cm2

=(275+154)2=\frac{ (275+154)}{2} cm2

= 4292\frac{429}{2} cm2 = 214.5214.5 cm2