Question

A toy car is tied to the end of an unstretched string of length a. When revolved, the toy car moves in a hori­zontal circle of radius 2a with time period T. If it is now revolved in a horizontal circle of radius 3a with a period T with the same force, then

• A. T = $\frac{\sqrt{3}}{2}T$
• B. T = $\sqrt{\frac{3}{2}}T$
• C. T = T
• D. T = $\frac{3}{2}$ T

Answer 1

Answer: (B)

T = $\sqrt{\frac{3}{2}}T$

Answer 2

$m2a\left( \frac{2\pi}{T} \right)^{2} = m3a\int_{0}^{l}{xdx = so\frac{T'}{T} = \sqrt{\frac{3}{2}}}$