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Question: A tower subtends an angle of 30<sup>o</sup> at a point distant d from the foot of the tower and on t...

A tower subtends an angle of 30o at a point distant d from the foot of the tower and on the same level as the foot of the tower. At a second point h vertically above the first, the depression of the foot of the tower is 60o. The height of the tower is

A

h3\frac { h } { 3 }

B

h3d\frac { h } { 3 d }

C

3h3 h

D

3hd\frac { 3 h } { d }

Answer

h3\frac { h } { 3 }

Explanation

Solution

Let CD is tower

From BCD,Hd=tan30\triangle B C D , \frac { H } { d } = \tan 30 ^ { \circ } ........(i)

and from ABD,hd=tan60\triangle A B D , \frac { h } { d } = \tan 60 ^ { \circ } ........(ii)

Divide equation (ii) from equation (i), we have H=h3H = \frac { h } { 3 }