Question
Question: A tower stands vertically on the ground. From a point on the ground which is 30m away from the foot ...
A tower stands vertically on the ground. From a point on the ground which is 30m away from the foot of the tower, the angle of elevation of the top of the tower is found to be 45∘ . Find the height of the tower.
A. 15
B. 40
C. 30
D. 20
Solution
Hint: This is a problem based on the application of trigonometry. In these types of problems, it is necessary to draw a diagram and then observe what we are told to find and what we are already given. Then we have to use the concept of trigonometric ratios. Here we will use tanθ=BasePerpendicular
Complete step-by-step answer:
Let us try to draw the figure as discussed in the question,
Here BC is the distance from the point of elevation C to the tower located at point B,
The height of the tower is AP which is also the perpendicular in the right-angled triangle ABC
Here θ is the point of elevation and according to the question θ=45∘ Now as we are told to find the value of height of tower which is also the perpendicular and we are given the base and the angle of elevation. It is best to use trigonometric function named tangent which is also equals to BasePerpendicular
So as we know that