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Question

Physics Question on Moving charges and magnetism

A toroid has 500 turns per metre length. If it carries a current of 2A, the magnetic energy density inside the toroid is

A

6.28J/m36.28 \,J/m^3

B

0.628J/m30.628\, J/m^3

C

3.14J/m33.14 \,J/m^3

D

0.314J/m30.314\, J/m^3

Answer

0.628J/m30.628\, J/m^3

Explanation

Solution

Magnetic field inside a toroid
B=μ0nlB=\mu_{0} nl
Magnetic energy density inside the toroid is
u0=B22μ0=μ02n2I22μ0=μ0n2I22u_{0}=\frac{B^{2}}{2 \mu_{0}}=\frac{\mu _{0} ^{2}n^{2} I^{2}}{2 \mu_{0}}=\frac{\mu_{0}n^{2}I^{2}}{2}
=4π×107×(500)2×222=0.628Jm3=\frac{4\pi\times10^{-7}\times\left(500\right)^{2}\times2^{2}}{2}=0.628 \, J m^{-3}