Question

A tin chloride Q undergoes the subsequent reaction (not balanced)
$Q+C{{l}^{-}}\text{ }\to \text{ }X$
$Q+\text{ }M{{e}_{3}}N\to \text{ }Y$
$Q+\text{ }CuC{{l}_{2}}\text{ }\to \text{ }Z+\text{ }CuCl$
X is a monoanion having pyramidal geometry. Both Y and Z are neutral compounds. Choose the right options (this question has multiple correct option)
(A) The central atom in X is $s{{p}^{3}}$ hybridized
(B) There is a dative bond in Y
(C) The oxidation number of the central atom in Z is +2
(D) The central atom in Z has one lone pair of electrons

Answer 1

As we all know the formula for tin chloride is $SnC{{l}_{2}}$ (where during this question performs some reactions). Monoanion is mentioned as an ion having one charge. Where pyramidal geometry is made by a polyhedron formed by connecting a polygonal base and some extent, called the apex.

Complete step by step answer: In the unified state, the metals are meant to exist as they are present in nature within their compounds. The reactive metals typically exist inside their compound appearance. In the cumulative state the metals are found as oxides, carbonates, sulphides, silicates, phosphates etc. within the planet's crust. Composite Q is $SnC{{l}_{2}}$.
The given reactions are
$SnC{{l}_{2}}+C{{l}^{-}}\to \underset{\left( X \right)}{\mathop{SnCl_{3}^{-}}}\,$
$SnC{{l}_{2}}+M{{e}_{3}}N\to \underset{\left( Y \right)}{\mathop{M{{e}_{3}}\overset{+}{\mathop{N}}\,-\overset{-}{\mathop{Sn}}\,C{{l}_{2}}}}\,$
$SnC{{l}_{2}}+2CuC{{l}_{2}}\to SnC{{l}_{4}}+\underset{\left( Z \right)}{\mathop{2CuCl}}\,$
Hybridisation of $Sn$ in $SnCl_{3}^{-}$is $s{{p}^{3}}$(X)

Trimethylamine forms a co-ordinate bond with $Sn$ in $SnCl_{2}^{{}}$(Y),
and in $SnCl_{4}^{{}}$ there's no lone pair on the central atom of $SnCl_{4}^{{}}$ (Z).
Hence, (Q), (X), (Y) and (Z) are $SnC{{l}_{2}}$, $SnCl_{3}^{-}$, $SnCl_{2}^{{}}$ and $SnCl_{4}^{{}}$ respectively.
Tin (II) chloride is a white crystalline solid with the formula $SnC{{l}_{2}}$ and is also known as stannous chloride. It forms a stable dihydrate, but aqueous solutions, especially if acidic, tend to undergo hydrolysis. $SnC{{l}_{2}}$ is commonly used as a reducing agent, and for tin-plating in electrolytic baths.

Note: Tin ($Sn$) may well be a bunch 14 elements, it show $s{{p}^{3}}$ hybridisation with two bond pairs between $s{{p}^{3}}-p$ orbital of two chlorine atoms and remaining two lone pairs are present. the shape of the molecule is V-shaped.