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Question

Question: \(a \times \lbrack a \times (a \times \mathbf{b})\rbrack\) is equal to...

a×[a×(a×b)]a \times \lbrack a \times (a \times \mathbf{b})\rbrack is equal to

A

(a×a).(b×a)(a \times a).(b \times a)

B

a.(b×a)b.(a×b)a.(b \times a) - b.(a \times b)

C

[a.(a×b)]a\lbrack a.(a \times b)\rbrack a

D

(a.a)(b×a)(a.a)(b \times a)

Answer

(a.a)(b×a)(a.a)(b \times a)

Explanation

Solution

a×[a×(a×b)]=a×{(a.b)a(a.a)b}=(a.b)(a×a)(a.a)(a×b)=(a.b)0+(a.a)(b×a)\mathbf{a} \times \lbrack\mathbf{a} \times (\mathbf{a} \times \mathbf{b})\rbrack = \mathbf{a} \times \{(\mathbf{a}.\mathbf{b})\mathbf{a} - (\mathbf{a}.\mathbf{a})\mathbf{b}\} = (\mathbf{a}.\mathbf{b})(\mathbf{a} \times \mathbf{a}) - (\mathbf{a}.\mathbf{a})(\mathbf{a} \times \mathbf{b}) = (\mathbf{a}.\mathbf{b})0 + (\mathbf{a}.\mathbf{a})(\mathbf{b} \times \mathbf{a})

=(a.a)(b×a)= (\mathbf{a}.\mathbf{a})(\mathbf{b} \times \mathbf{a}).