Question
Question: A ticket is drawn from a bag containing \(100\) tickets. The tickets are numbered from one to hundre...
A ticket is drawn from a bag containing 100 tickets. The tickets are numbered from one to hundred. What is the probability of getting a ticket with a number divisible by 10?
A. 101
B. 51
C. 201
D. None
Solution
To find the probability, first we will write the sample space S for tickets. Then, we will consider the event E that gets a ticket with a number divisible by 10. We will find the required probability by using the definition. That is, required probability =n(S)n(E) where n(E) is the number of favourable (desired) outcomes and n(S) is the number of total outcomes.
Complete step-by-step solution:
In this problem, it is given that a bag containing 100 tickets and the tickets are numbered from one to hundred. So, one can get a ticket with a number between 1 and 100. The sample space is the set of all possible outcomes. Therefore, in this problem sample space for tickets is S = \left\\{ {1,2,3,...,100} \right\\}. Therefore, n(S)=100.
Now we will consider the event E that gets a ticket with a number divisible by 10. That is, our desired outcome is a number divisible by 10. We know that between 1 and 100, the numbers 10,20,30,40,50,60,70,80,90,100 are divisible by 10. We can see that these are 10 numbers. Therefore, n(E)=10.
Now we are going to find the probability of an event E by using the definition. That is, P(E)=n(S)n(E).
⇒P(E)=10010
⇒P(E)=101
Hence, the probability that getting a ticket with a number divisible by 10 is 101.
Hence, option A is the correct answer.
Note: In this problem, if we have to find the probability that getting a ticket with a number whose unit digit 0 then the answer will be the same. That is, probability of getting a ticket with a number whose unit digit 0 is also 101. In this problem, if we have to find the probability of getting a ticket with a multiple of 10 then the answer will be the same. That is, the probability of getting a ticket with a number multiple of 10 is also 101.