Question

A thin wire of resistance 4 ohm is bent to form a circle. The resistance across any diameter is:
A.4 ohm
B.2 ohm
C.1 ohm
D.8 ohm

Answer 1

Here, we calculate the electric resistance with the expression of the parallel circuit.
$\dfrac{1}{R} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}}$

Complete answer:
According to the question
A thin wire having an electric resistance of 4 ohm is bent and formed a circle. So, the length of the wire converts to the circumference.
So, here’s the diagram

Here the ACB and ACD are having equal electric resistance, here’s the diameter is AB and we have to calculate the resistance across the diameter:
Resistance is equal to 4 ohm.
So, the ACB and ACD have a resistance of 2 ohm and 2 ohm each.
It is parallel connection,
So, we use this expression
$\dfrac{1}{R} = \dfrac{1}{{{R_1}}} + \dfrac{1}{{{R_2}}}$
Here, $R_1$ is equal to 2 ohm
And $R_2$ is equal to 2ohm
R is the resistance across diameter.
$\dfrac{1}{R} = \dfrac{1}{2} + \dfrac{1}{2}$
$\Rightarrow \dfrac{1}{R} = 1$
$\Rightarrow R = 1\Omega$
Here, the resistance across diameter is 1 ohm

So, the option (C) is correct.

Note:
The electric resistance depends on this factor:
The temperature of the conductor,
The cross sectional area of the conductor, as well as the thickness,
The length of the conductor,
The nature of the material of the conductor,
The electric resistance increases with the increasing of the length of the wire and the thickness of the wire decreases.
We can reduce the resistance of the wire in many different ways. We can use thicker wire because of their thickness. There is an increase of the cross sectional area, we can lower the temperature of the material or we can change the material.
A good wire has a resistance of less than 10 ohm and the isolated conductor offers a resistance of 1 mega ohm or more.