Solveeit Logo

Question

Question: A thin spherical shell lying on a rough horizontal surface is hit by a cue in such a way that line o...

A thin spherical shell lying on a rough horizontal surface is hit by a cue in such a way that line of action passes through the centre of the shell. As a result shell starts moving with a linear speed v without any initial angular velocity. Find the linear velocity to the shell when it starts pure rolling.

A

35v\frac{3}{5}v

B

25v\frac{2}{5}v

C

45v\frac{4}{5}v

D

None

Answer

35v\frac{3}{5}v

Explanation

Solution

vf = v - Ffmt\frac{F_{f}}{m}t ……….. (i) F1r = α

or Ffr = 23mr2α\frac{2}{3}mr^{2}\alpha

or α = 32Ffmrω=0+αt\frac{3}{2}\frac{F_{f}}{mr}\omega = 0 + \alpha t

or ω = 32Ffmr\frac{3}{2}\frac{F_{f}}{mr}t

or rω = vf = 3Ff2m\frac{3F_{f}}{2m}t ………. (ii)

From eq. (i) and (ii) vf = 35v.\frac{3}{5}v.