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Question

Physics Question on Ray optics and optical instruments

A thin prism R1R_{1} of angle 44^{\circ} and refractive index 1.541.54^{\circ} is combined with another thin prism P2P_{2} of refractive index 1.721.72 to produce dispersion without deviation. The angle of P2P_{2} is

A

44^{\circ}

B

5.335.33^{\circ}

C

2.62.6^{\circ}

D

33^{\circ}

Answer

33^{\circ}

Explanation

Solution

Angle of deviation δ=(n1)A\delta=(n-1) A. Dispersion produced by both the prism's will be equal. (n11)A1=(n21)A2\left(n_{1}-1\right) A_{1}=\left(n_{2}-1\right) A_{2} A2=(n11)A1(n21)\Rightarrow A_{2}= \frac{\left(n_{1}-1\right) A_{1}}{\left(n_{2}-1\right)} =(1.541)(1.721)=3=\frac{(1.54-1)}{(1.72-1)}=3^{\circ} Hence, the angle of prism P2P_{2} is 33^{\circ}