Question

A thin prism made of glass is dipped in water, then minimum deviation with respect to air by it will be (given m_glass = $\frac { 3 } { 2 }$&m_water = $\frac { 4 } { 3 }$)

• A. $\frac { 1 } { 2 }$
• B. $\frac { 1 } { 4 }$
• C. $\frac { 1 } { 8 }$
• D. $\frac { 1 } { 16 }$

Answer 1

Answer: (B)

$\frac { 1 } { 4 }$

Answer 2

In air

d = (m – 1) A = … (i)

In water

d' = $\left( \frac { \mu _ { \text {glass } } } { \mu _ { \text {water } } } - 1 \right)$ A = …(ii)

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