Question
Question: A thin prism having refracting angle \({10^ \circ }\) is made of glass of refractive index \(1.42\)....
A thin prism having refracting angle 10∘ is made of glass of refractive index 1.42. This prism is combined with another thin prism of glass of refractive index 1.7. This combination produces dispersion without deviation. The refracting angle of the second prism should be:
(A) 10∘
(B) 4∘
(C) 6∘
(D) 8∘
Solution
Use the relation given below and substitute the values of the refractive angle of the first prism and the refractive index of the two prisms in it. The output provides the refractive angle of the second prisms. This both the prisms make the light wave disperse in it.
Useful formula:
The refractive relation in the prism is given by
θ1(r1−1)=θ2(r2−1)
Where θ1 is the refractive angle of the first prism, θ2 is the refractive angle of the prism two, r1 is the refractive index of the glass of the first prism and r2 is the refractive index of the glass of the second prism.
Complete step by step solution:
It is given that the
Refractive angle of the first prism, θ1=10∘
The refractive index of the glass in the first prism, r1=1.42
The refractive index of the glass in the first prism, r1=1.7
Using the formula of the relation,
θ1(r1−1)=θ2(r2−1)
Substituting the known values in the above relation,
10(1.42−1)=θ2(1.7−1)
By performing the simplification inside the brackets
10(0.42)=θ2(0.7)
By grouping the similar terms on one side and the unknown parameter on the other side.
0.710×0.42=θ2
By performing the simple arithmetic operations,
θ2=6∘
Hence the refractive index of the second prism is obtained as 6∘.
Thus the option (C) is correct.
Note: The disperse index of the water is 1. Thus the relation contains this term. It is defined as the layer of the object that slowdowns the speed of the light through it and maintains its dispersion there. In this condition, the two prisms are connected together with a high refractive index making light to disperse inside.