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Question: A thin mica sheet of thickness \(2 \times 10^{- 6}\)m and refractive index (μ = 1.5) is introduced i...

A thin mica sheet of thickness 2×1062 \times 10^{- 6}m and refractive index (μ = 1.5) is introduced in the path of the first wave. The wavelength of the wave used is 5000Å. The central bright maximum will shift

A

2 fringes upward

B

2 fringes downward

C

10 fringes upward

D

None of these

Answer

2 fringes upward

Explanation

Solution

By using shift Δx=pλ(μ1)t\Delta x = \frac{p}{\lambda}(\mu - 1)t

Δx=β5000×1010(1.51)×2×106=2β\Delta x = \frac{\beta}{5000 \times 10^{- 10}}(1.5 - 1) \times 2 \times 10^{- 6} = 2\beta

Since the sheet is placed in the path of the first wave, so shift will be 2 fringes upward.