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Question

Physics Question on Kinetic Energy

A thin hollow sphere of mass m is completely filled with a liquid of mass mm. When the sphere rolls with a velocity vv, kinetic energy of the system is (neglect friction)

A

12mv2\frac {1}{2} mv^2

B

mv2mv^2

C

43mv2\frac {4}{3} mv^2

D

45mv2\frac {4}{5} mv^2

Answer

43mv2\frac {4}{3} mv^2

Explanation

Solution

Total energy =KE+= KE + rotational KE KE =12(2m)v2+13mv2=\frac{1}{2}(2 m ) v^{2}+\frac{1}{3} m v^{2} =43mv2 =\frac{4}{3} m v^{2}