Question

A thin glass prism of m = 1.5 is immersed in water of m = 1.33. The ratio of deviation of the ray in water to that in air for the same prism is-

• A. 1 : 4
• B. 1 : 2
• C. 1 : 8
• D. 1 : 3

Answer 1

Answer: (A)

1 : 4

Answer 2

In air d = (1.5 – 1) A = A/2

In water d = $\left( \frac { \mu _ { \mathrm { g } } } { \mu _ { \mathrm { w } } } - 1 \right) \mathrm { A } = \left( \frac { 1.5 } { 1.33 } - 1 \right) \mathrm { A } = \frac { \mathrm { A } } { 8 }$

$\frac { \delta \text { in water } } { \delta \text { in air } } = \frac { 1 } { 4 }$