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Question: A thin film of liquid polymer, \(n = 1.25\) coats a slab of Pyrex, \(n = 1.50\). White light is inci...

A thin film of liquid polymer, n=1.25n = 1.25 coats a slab of Pyrex, n=1.50n = 1.50. White light is incident perpendicularly on the film. In the reflection, full destructive interference occurs for λ=600nm\lambda = 600\,nm and full constructive interference occurs for λ=700nm\lambda = 700\,nm. What is the thickness of the polymer film?

(A) 120nm120\,nm
(B) 280nm280\,nm
(C) 460nm460\,nm
(D) 840nm840\,nm

Explanation

Solution

This problem is related to thin film interference, if the light is incident from one medium to another medium, the reflection is full destructive interference will occur at λ=600nm\lambda = 600\,nm and the full constructive interference occurs for λ=700nm\lambda = 700\,nm, then the thickness of the film is determined by using the thin film interference formula.

Formulae Used:
By thin film interference, the thickness of the film is given by,
For constructive interference,
2t=mλn2t = \dfrac{{m\lambda }}{n}
Where, tt is the thickness of the film, mm is the order of the interference, λ\lambda is the wavelength for constructive interference and nn is the refractive index.

Complete step-by-step solution:
Given that,
Refractive index of liquid polymer, n1=1.25{n_1} = 1.25
Refractive index of slab of Pyrex, n2=1.50{n_2} = 1.50
Wavelength for destructive interference, λ1=600nm{\lambda _1} = 600\,nm
Wavelength for constructive interference, λ2=700nm{\lambda _2} = 700\,nm

Thin-film interference is the interference of light waves reflecting off the top surface of a film with the waves reflecting from the bottom surface.
By thin film interference, the thickness of the film is given by,
For constructive interference,
2t=mλ2n1..................(1)2t = \dfrac{{m{\lambda _2}}}{{{n_1}}}\,..................\left( 1 \right)
For constructive interference, the wavelength is λ2{\lambda _2} and we have to find the thickness of the polymer film, so take the refractive index of polymer n1{n_1}.
By substituting the wavelength and refractive index value in the equation (1), then
2t=m×7001.252t = \dfrac{{m \times 700}}{{1.25}}
Here, mm is the order of interference, so take m=3m = 3, and substitute in the above equation, then
2t=3×7001.252t = \dfrac{{3 \times 700}}{{1.25}}
On multiplying the numerator in the above equation, then
2t=21001.252t = \dfrac{{2100}}{{1.25}}
Now dividing the RHS, then the above equation is written as,
2t=16802t = 1680
By keeping the term tt in one side and the other terms in other side, then
t=16802t = \dfrac{{1680}}{2}
By dividing the terms, then
t=840nmt = 840\,nm
Thus, the above equation shows the thickness of the polymer film.
Hence, the option (D) is the correct answer.

Note:- The thickness of the thin film is also determined by using the thin film interference formula for destructive interference. And the formula for destructive interference is 2t=(m+12)(λn)2t = \left( {m + \dfrac{1}{2}} \right)\left( {\dfrac{\lambda }{n}} \right) by using this formula the thickness of the thin film can be determined.