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Question

Physics Question on Electric charges and fields

A thin disc of radius b=2ab\, = \,2a has a concentric hole of radius 'aa' in it (see figure). It carries uniform surface charge 'σ\sigma' on it. If the electric field on its axis at height 'hh' (h<<a)(h < < a) from its centre is given as 'ChCh' then value of 'CC' is :

A

σaϵ0\frac{\sigma}{a\epsilon_{0}}

B

σ2aϵ0\frac{\sigma}{2a\epsilon_{0}}

C

σ4aϵ0\frac{\sigma}{4a\epsilon_{0}}

D

σ8aϵ0\frac{\sigma}{8a\epsilon_{0}}

Answer

σ4aϵ0\frac{\sigma}{4a\epsilon_{0}}

Explanation

Solution