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Question: A thin copper wire of length \[L\] increases in length by 1% when heated from temperature \[{T_1}\]t...

A thin copper wire of length LL increases in length by 1% when heated from temperature T1{T_1}to T2{T_2} . What is the percentage change in area when a thin copper plate having dimension 2L×L2L \times L is heated from T1{T_1} to T2{T_2} ?
1%
2%
3%
4%

Explanation

Solution

All the metal when they are heated expands and the factor by which their length changes is called coefficient of linear expansion (α\alpha ) . Since the length of the metal is changing ,its area also increases by a factor called coefficient of areal expansion (β\beta ).

Step by step solution :- initial length of copper wire = LL
Length after heating from temperature T1{T_1}to T2{T_2} = L+(1%  of  L)L + (1\% \;of\;L)=
(1%  of  L)=LαΔT(1\% \;of\;L) = L\alpha \Delta T

αΔT=1100\alpha \Delta T = \dfrac{1}{{100}}………..(1)
Initial area AA=2L×L2L \times L
Area after heating heated from temperature T1{T_1}to T2{T_2} = A+  AβΔTA + \;A\beta \Delta T
Change in area after heating heated from temperature T1{T_1}to T2{T_2} =AA-(A+  AβΔTA + \;A\beta \Delta T)
Change in area after heating heated from temperature T1{T_1}to T2{T_2} = AβΔTA\beta \Delta T
We know that β=2α\beta = 2\alpha
Putting the value β=2α\beta = 2\alpha
Percentage % change in area of plate AβΔTA\dfrac{{A\beta \Delta T}}{A}=βΔT\beta \Delta T
βΔT=2αΔT\beta \Delta T = 2\alpha \Delta T
αΔT=1100\alpha \Delta T = \dfrac{1}{{100}}
2αΔT=21002\alpha \Delta T = \dfrac{2}{{100}}= 2%
Hence , the percentage change in area of the copper plate of dimension 2L×L2L \times Lis 2%.

Thus option (B) is the correct answer.

Note:- In solid , liquids or gases there is another type of expansion observed when heated from temperature T1{T_1}to T2{T_2} that is volume expansion. The constant by which the volume changes as we change the temperature from T1{T_1}to T2{T_2}is coefficient of volume expansion Υ\Upsilon .
For the isotropic solid materials ( whose lattice structure is well in order ) there is a relation between linear , areal & volumetric coefficients of expansion such that α:β:Υ::1:2:3\alpha :\beta :\Upsilon ::1:2:3

Thermal expansion of an isotropic object may be imagined as a photographic enlargement.
Liquids usually expand more than solids because the intermolecular forces in liquids are weaker than in solids.

Rubber contracts on heating because in rubber as temperature increases , the amplitude of the transverse vibrations increases more than the amplitude of the longitudinal vibrations.

In cold countries water pipes sometimes burst , because water expands on freezing.