Question
Physics Question on electrostatic potential and capacitance
A thin conducting ring of radius R is given a charge + The electric field at the center O of the ring due to the charge on the part AKB of the ring is E. The electric field at the center due to the charge on the part ACDB of the ring is
A
E along KO
B
3E along OK
C
3E along KO
D
E along OK
Answer
E along OK
Explanation
Solution
The fields at O due to AC and BD cancel each other.
The field due to CD is acting in the direction OK and equal in magnitude to E due to AKB.