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Question: A thin circular ring of area A is held perpendicular to a uniform magnetic field of induction B. A s...

A thin circular ring of area A is held perpendicular to a uniform magnetic field of induction B. A small cut is made in ring and a galvanometer is connected across the ends such that total resistance of the circuit is R. When the ring is suddenly squeezed to zero area, the charge flowing through the galvanometer is-

A

BRA\frac { \mathrm { BR } } { \mathrm { A } }

B

C

ABR

D

B2 AR2\frac { \mathrm { B } ^ { 2 } \mathrm {~A} } { \mathrm { R } ^ { 2 } }

Answer

Explanation

Solution

f1 = BA cos00 = BA

f 2 = B(0) cosq = 0

Ž qind = – dϕR\frac { \mathrm { d } \phi } { \mathrm { R } } = BAR\frac { \mathrm { BA } } { \mathrm { R } }