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Question: A thermodynamic system goes from states (i) P1, V to 2P1, V (ii) P, V1 to P, 2V1. Then work done in ...

A thermodynamic system goes from states (i) P1, V to 2P1, V (ii) P, V1 to P, 2V1. Then work done in the two cases is

A

Zero, Zero

B

Zero, – PV1

C

– PV1, Zero

D

–PV1, –P1V1

Answer

Zero, – PV1

Explanation

Solution

case (i) Δ\DeltaV = 0, W = 0

case (ii) P = constant, W = – P(2V1 –V1) = – PV1