Question

A thermodynamic process is carried out from an original state D to an intermediate state E by the linear process shown in figure.

The total work is done by the gas from D to E to F is

• A. 100 J
• B. 800 J
• C. 300 J
• D. 250 J

Answer 1

Answer: (B)

800 J

Answer 2

: Total work done by the gas from D to E to F is equal to the area of

the area of $\Delta D E F = \frac { 1 } { 2 } D F \times E F$

Here, DF change in pressure $= 600 - 200$ $= 400 \mathrm { Nm } ^ { - 1 }$

Also, EF = change in volume $= 7 m ^ { 3 } - 3 m ^ { 3 } = 4 m ^ { 3 }$

Area of

Thus, the total work done by the gas form D to E to F is 800 J.