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Question: A thermo couple develops 40 μV/kelvin. If hot and cold junctions be at 40<sup>o</sup>C and 20<sup>o<...

A thermo couple develops 40 μV/kelvin. If hot and cold junctions be at 40oC and 20oC respectively then the emf develops by a thermopile using such 150 thermo couples in series shall be

A

150 Mv

B

80 Mv

C

80 Mv

D

120 Mv

Answer

120 Mv

Explanation

Solution

The temperature difference is 200C = 20 K. So that thermo emf developed E = =40μVK×20K=800μV.= 40\frac{\mu V}{K} \times 20K = 800\mu V.

Hence total emf = 150 × 800 = 12 × 104 μV = 120 Mv