Question

A) The peak voltage of an ac supply is $300\,V$. What is the rms voltage?
B) The rms value of current in an ac circuit is $10\,A$. What is the peak current?

Answer 1

Here we have to use the formula and concepts of rms voltage, peak voltage and rms current.
The RMS (Root-Mean-Square) value is the successful estimation of the sum of the waveform. It is equivalent to the level of the DC signal that would give a similar mean power as the periodic signal.

Complete step-by-step answer:
The highest voltage value on any waveform is known as peak voltage. It is a power quality problem that arises when devices that use Pulse Width Modulation, such as a variable frequency motor, are added to the power grid.
On the off chance that the rms voltage is known, at that point the peak voltage can be discovered utilizing this formula where ${V_{rms}}$ is the rms voltage. Hence, peak voltage is equivalent to the square root of multiple times the rms voltage.
RMS, or root mean square (likewise called successful), voltage is a strategy for indicating a voltage sine waveform (AC waveform) as an identical voltage which represents the DC voltage value that will deliver a similar warming impact, or power dissipation, in circuit, as this AC voltage.
The comparison between AC and DC can be done by rms value.
The RMS voltage $\left( {{v_{rms}}} \right)$ of a sinusoidal waveform is determined by multiplying the peak voltage value by $0.7071$.
Given,
${V_{peak}} = 300\,V$
${i_{rms}} = 10\,A$
A) ${V_{rms}} = \dfrac{{{V_{peak}}}}{{\sqrt 2 }} \\\ = \dfrac{{300}}{{\sqrt 2 }} \\\ = 212.13\,V$
B) ${I_{peak}} = {i_{rms}}\sqrt 2 \\\ = 10\sqrt 2 \\\ = 14.14\,A$

Note: Here we have to be careful as to what value is given in the question. Also we have to check the units of rms values and peak values. The RMS current value can likewise be characterized as the "estimation of the immediate current that dissipates the same type of force in a resistor". The RMS for one phase of the periodic function is equal to the RMS for one phase of the function.