A tetrahedron has vertices at 0(0,0,0), A(1,2,1), B(2,1,3) a... | Mathematics | SolveeIt | Solveeit

Today, August 18

Question

A tetrahedron has vertices at 0(0,0,0), A(1,2,1), B(2,1,3) and C(-1,1,2) then the angle between the faces 0AB and ABC will be

A

$cos^{-1}[\frac{19}{35}]$

B

$cos^{-1}[\frac{17}{31}]$

C

30o

D

90o

Answer

$cos^{-1}[\frac{19}{35}]$

Explanation

Solution

The correct option is (A): $cos^{-1}[\frac{19}{35}]$