Question

A test charge is moved from lower potential point to a higher potential point. The potential energy of test charge will

• A. remain the same
• B. increase
• C. decrease
• D. become zero

Answer 1

Answer: (B)

increase

Answer 2

A test charge is moved from a lower potential point to a higher potential point. The potential energy of the test charge will increase. Because $U = Q V$ $\because Q =+ 1 , \quad U = V$ At high potential will high energy and at low potential will have low energy.

When a test charge is moved from a lower potential point to a higher potential point, its potential energy will increase.

The potential energy of a test charge in an electric field is given by the equation:

PE = qV

where PE is the potential energy, q is the charge of the test charge, and V is the potential difference.

In this case, as the test charge is moved from a lower potential point to a higher potential point, the potential difference (V) increases. Since the charge (q) remains the same, the potential energy (PE) will also increase.

Therefore, the potential energy of the test charge will increase when it is moved from a lower potential point to a higher potential point.