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Question: A tank of base area 4 m<sup>2</sup> is initially filled with water up to height 2 m. An object of un...

A tank of base area 4 m2 is initially filled with water up to height 2 m. An object of uniform cross-section 2 m2 and height 1 m is now suspended by wire into the tank, keeping distance between base of tank and that of object 1 m. Density of the object is 2000kg/m3. Take atmospheric pressure 1 × 105N/m2; g = 10 m/s2

The downward force exerted by the water on the top surface of the object is:

A

2.0 × 105N

B

2.1 × l05N

C

2.2 × 105N

D

2:3 × l05N

Answer

2.1 × l05N

Explanation

Solution

By conservation of volume 4 × h = 4 × 2 + 2 × 1 = 10

h = 2.5m

Pressure at top of the object = P0 + 0.5 × 1000 × 10

= 1.05 × 105N/m2 F = P1A

= 1.05 × 105 × 2 = 2.1 × 105N