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Question: A tangent to the parabola x<sup>2</sup> = 4ay meets the hyperbola xy = k<sup>2</sup> in two points P...

A tangent to the parabola x2 = 4ay meets the hyperbola xy = k2 in two points P and Q. Then the middle point of PQ lies on a:

A

Circle

B

A parabola

C

An ellipse

D

Hyperbola

Answer

A parabola

Explanation

Solution

Let (a, b) be the middle points.

\ Equation of chord bisected is S1 = T

Ž y = αβ\frac { - \alpha } { \beta }+ 2a which is tangent to

x2 = 4a

where D = 0

Ž b2 = or, y2

= – (which is parabola)