Question
Question: A tangent to the parabola x<sup>2</sup> = 4ay meets the hyperbola xy = k<sup>2</sup> in two points P...
A tangent to the parabola x2 = 4ay meets the hyperbola xy = k2 in two points P and Q. Then the middle point of PQ lies on a:
A
Circle
B
A parabola
C
An ellipse
D
Hyperbola
Answer
A parabola
Explanation
Solution
Let (a, b) be the middle points.
\ Equation of chord bisected is S1 = T
Ž y = β−α+ 2a which is tangent to
x2 = 4a
where D = 0
Ž b2 = or, y2
= – (which is parabola)