Question
Mathematics Question on Coordinate Geometry
A tangent PT is drawn to the circle x2 + y2 = 4 at the point P(√3, 1). If a straight line L which is perpendicular to PT is a tangent to the circle (x- 3)2 + y2 = 1, then a possible equation of L is
A
x - √3y = 1
B
x- √3y = 4
C
x - √3y = -1
D
x-√3y = 7
Answer
x - √3y = 1
Explanation
Solution
The correct option is: (A) x - √3y = 1