Question

A system is taken through a cyclic process represented by a circle as shown. The heat absorbed by the system is –

• A. p × 10³ J
• B. $\frac { \pi } { 2 }$J
• C. 4p × 10² J
• D. p J

Answer 1

Answer: (B)

$\frac { \pi } { 2 }$J

Answer 2

In cyclic process DQ = Work done = Area inside the closed curve. Treat the circle as an ellipse of area = $\frac { \pi } { 4 }$(P₂ – P₁) (V₂ – V₁)

̃ DQ = $\frac { \pi } { 4 }$ {(150–50) × 10³} = $\frac { \pi } { 2 }$ J