Question
Question: A system is provided with 200 cal of heat and the work done by the system on the surrounding is 40 J...
A system is provided with 200 cal of heat and the work done by the system on the surrounding is 40 J. Then its internal energy
A
Increases by 600 J
B
Decreases by 800 J
C
Increases by 800 J
D
Decreases by 50 J
Answer
Increases by 800 J
Explanation
Solution
ΔQ=ΔU+ΔW
∵ΔQ=200cal=200×4.2=840Jand ΔW=40J
⇒ΔU=ΔQ−ΔW=840−40=800J