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Question

Question: A system is provided with 200 cal of heat and the work done by the system on the surrounding is 40 J...

A system is provided with 200 cal of heat and the work done by the system on the surrounding is 40 J. Then its internal energy

A

Increases by 600 J

B

Decreases by 800 J

C

Increases by 800 J

D

Decreases by 50 J

Answer

Increases by 800 J

Explanation

Solution

ΔQ=ΔU+ΔW\Delta Q = \Delta U + \Delta W

ΔQ=200cal=200×4.2=840J\because\Delta Q = 200cal = 200 \times 4.2 = 840Jand ΔW=40J\Delta W = 40J

ΔU=ΔQΔW=84040=800J\Delta U = \Delta Q - \Delta W = 840 - 40 = 800J