Question
Physics Question on Electric charges and fields
A system has two charges qA=2.5×10−7C and qB=−2.5×10−7C located at points A:(0,0,−15cm) and B:(0,0+15cm) , respectively. What is the magnitude and direction of electric dipole moment of the system ?
A
7.5×10−8cm , from positive to negative charge
B
0.75×10−8cm , from negative to positive charge
C
7.5×10−8cm , from negative to positive charge
D
0.75×10−8cm , cm, from positive to negative charge
Answer
7.5×10−8cm , from negative to positive charge
Explanation
Solution
qA=2.5×10−7C
qB=−2.5×10−7C
Total charge o f the system, q=qA+qB=0
Distance between two charges at points A and B,
d=15+15=30cm=0.3m
Electric dipole moment of the system is given by,
p=qA×d=qB×d
=2.5×10−7×0.3
=7.5×10−8cm, along positive z-axis