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Question: A system absorbs 50 kJ heat and does 20 kJ of work. What is the net change in the internal energy of...

A system absorbs 50 kJ heat and does 20 kJ of work. What is the net change in the internal energy of the system?

A

Increase by 30 kJ

B

Decrease by 30 kJ

C

Increase by 70 kJ

D

Decrease by 70 Kj

Answer

Increase by 30 kJ

Explanation

Solution

: ΔU=dq+(W)=50+(20)=30kJ\Delta U = dq + ( - W) = 50 + ( - 20) = 30kJ