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Question: A sum of money invested at compound interest amounts to Rs. 800 in 3 years and to Rs. 840 in 4 years...

A sum of money invested at compound interest amounts to Rs. 800 in 3 years and to Rs. 840 in 4 years. The rate of interest per annum is-
A. 3%
B. 4%
C. 5%
D. 6%

Explanation

Solution

Hint: We will simply use the formula of compound interest i.e. A=P(1+r100)nA = P{\left( {1 + \dfrac{r}{{100}}} \right)^n}, where A stands for the value of amount, P stands for the principal amount, r stands for the rate and n stands for the number of years or number of intervals and we will find the rate of interest per annum as asked by the question.

Complete step-by-step answer:
Let the rate of interest per annum be r.
As we know the formula for compound interest is A=P(1+r100)nA = P{\left( {1 + \dfrac{r}{{100}}} \right)^n}. The compound interest for the first 3 years is given as 800. Rate will be r and principal amount will be P. We will put these values in the formula for compound interest we will have-
800\to 800 = P(1+r100)3P{\left( {1 + \dfrac{r}{{100}}} \right)^3}
We will take this equation as equation 1, we get-
800=P(1+r100)3\to 800 = P{\left( {1 + \dfrac{r}{{100}}} \right)^3} (equation 1)
Now, the value of compound interest for four years is given as 840. Rate will be r and principal amount P. We will put these values in the formula for compound interest we will have-
840=P(1+r100)4\to 840 = P{\left( {1 + \dfrac{r}{{100}}} \right)^4}
We will take the above equation as equation 2, we will have-
840=P(1+r100)4\to 840 = P{\left( {1 + \dfrac{r}{{100}}} \right)^4} (equation 2)
Now, we will divide equation 1 by equation 2 in order to solve this further. After doing so we will have-
800840=P(1+r100)3P(1+r100)4  8084=1(1+r100)  2021=1(1+r100)  \to \dfrac{{800}}{{840}} = \dfrac{{P{{\left( {1 + \dfrac{r}{{100}}} \right)}^3}}}{{P{{\left( {1 + \dfrac{r}{{100}}} \right)}^4}}} \\\ \\\ \to \dfrac{{80}}{{84}} = \dfrac{1}{{\left( {1 + \dfrac{r}{{100}}} \right)}} \\\ \\\ \to \dfrac{{20}}{{21}} = \dfrac{1}{{\left( {1 + \dfrac{r}{{100}}} \right)}} \\\
By cross multiplication, we will have-
20(1+r100)=21  20+20r100=21  r5=1  r=5%  \to 20\left( {1 + \dfrac{r}{{100}}} \right) = 21 \\\ \\\ \to 20 + \dfrac{{20r}}{{100}} = 21 \\\ \\\ \to \dfrac{r}{5} = 1 \\\ \\\ \Rightarrow r = 5\% \\\
Thus, the rate of interest per annum is 5%.

Note: In such questions, let consider rate be r and apply the formula for compound interest i.e. A=P(1+r100)nA = P{\left( {1 + \dfrac{r}{{100}}} \right)^n}. The formula should be memorised in an exact manner and the values should be put correctly in order to get the correct answer.