Question

A suitable unit for gravitational constant is

• A. $kgmetre\sec^{- 1}{}$
• B. $Newtonmetre^{- 1}\sec$
• C. $Newtonmetre^{2}kg^{- 2}$
• D. $kgmetre\sec^{- 1}{}$

Answer 1

Answer: (C)

$Newtonmetre^{2}kg^{- 2}$

Answer 2

As $F = \frac{Gm_{1}m_{2}}{r^{2}}$ $\therefore$ $G = \frac{Fr^{2}}{m_{1}m_{2}}$

Substituting the unit of above quantities unit of G = $Newtonmetre^{2}kg^{- 2}$.