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Question

Physics Question on Ray optics and optical instruments

A students plots a graph between inverse of magnification 1/mm produced by a convex thin lens and the object distance uu as shown in figure. What was the focal length of the lens used?

A

bca\frac{b}{ca}

B

bca\frac{bc}{a}

C

cb\frac{c}{b}

D

bc\frac{b}{c}

Answer

cb\frac{c}{b}

Explanation

Solution

Lens formula,1v1u=1f\frac{1}{v}-\frac{1}{u}=\frac{1}{f}
or uv1=uf\frac{u}{v}-1=\frac{u}{f}
1m1=uf\Rightarrow \frac{1}{m}-1=\frac{u}{f}
or 1m(1f)u+1 \frac{1}{m}\left(\frac{1}{f}\right)u+1
this is the equation of a straight line whose slope
1f=bc\frac{1}{f}=\frac{b}{c}
f=cb\therefore f = \frac{c}{b}