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Question

Mathematics Question on Statistics

A student scores the following marks in five tests : 45,54,41,57,4345,54,41,57,43. His score is not known for the sixth test. If the mean score is 48 in the six tests, then the standard deviation of the marks in six tests is

A

103\frac{10}{\sqrt{3}}

B

1003\frac{100}{\sqrt{3}}

C

1003\frac{100}{3}

D

103\frac{10}{3}

Answer

103\frac{10}{\sqrt{3}}

Explanation

Solution

Let x be the 6th observation
\Rightarrow 45+54+41+57+43+x=48×6=28845 + 54 + 41 + 57 + 43 + x = 48 \times 6 = 288
x=48\Rightarrow x = 48
variance = =(xi26(xˉ)2)= \left(\frac{\sum x_{i}^{2}}{6} - \left(\bar{x}\right)^{2}\right)
variance=140246(48)2\Rightarrow variance = \frac{14024}{6} - \left(48\right)^{2}
=1003= \frac{100}{3}
standarddeviation=103\Rightarrow standard\, deviation = \frac{10}{\sqrt{3}}