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Physics Question on Waves

A student is performing an experiment using a resonance column and a tuning fork of frequency 244s1244 \,s ^{-1}. He is told that the air in the tube has been replaced by another gas (assume that the column remains filled with the gas). If the minimum height at which resonance occurs is (0.350±0.005)m(0.350\, \pm 0.005) \,m, the gas in the tube is (Useful information: 167RT=640J1/2mole1/2;140RT=590J1/2mole1/2\sqrt{167 RT }=640\, J ^{1 / 2} \,mole ^{-1 / 2} ; \sqrt{140 \,RT }=590\, J ^{1 / 2}\, mole ^{-1 / 2}. The molar masses MM in grams are given in the options. Take the values of 10M\sqrt{\frac{10}{ M }} for each gas as given there.)

A

Neon (M=20,1020=710)\left( M =20, \sqrt{\frac{10}{20}}=\frac{7}{10}\right)

B

Nitrogen (M=28,1028=35)\left(M=28, \sqrt{\frac{10}{28}}=\frac{3}{5}\right)

C

Oxygen (M=32,1032=916)\left(M=32, \sqrt{\frac{10}{32}}=\frac{9}{16}\right)

D

Argon (M=36,1036=1732)\left( M =36, \sqrt{\frac{10}{36}}=\frac{17}{32}\right)

Answer

Argon (M=36,1036=1732)\left( M =36, \sqrt{\frac{10}{36}}=\frac{17}{32}\right)

Explanation

Solution

=14vγRTM\ell=\frac{1}{4 v} \sqrt{\frac{\gamma RT }{ M }}
Calculations for 14vγRTM\frac{1}{4 v} \sqrt{\frac{\gamma RT }{ M }} for gases mentioned in options A,B,CA, B, C and DD, work out to be 0.459m,0.363m0.340m&0.348m0.459 \,m , 0.363\, m\,0.340\,m \& 0.348\, m respectively. As =(0.350±0.005)m;\ell=(0.350 \pm 0.005) \,m ;