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Question: A student found that the sulfate ion concentration in a solution of \[A{l_2}{\left( {S{O_4}} \right)...

A student found that the sulfate ion concentration in a solution of Al2(SO4)3A{l_2}{\left( {S{O_4}} \right)_3} was 0.22M0.22M . What was the concentration of Al2(SO4)3A{l_2}{\left( {S{O_4}} \right)_3} in the solution?

Explanation

Solution

Aluminium sulphate is an ionic compound consisting of aluminium and sulphate groups. From the balanced chemical equation, and the moles of sulphate group, aluminium atom, aluminium sulphate the concentration of Al2(SO4)3A{l_2}{\left( {S{O_4}} \right)_3} can be determined.

Complete answer:
Aluminium is a metal that can lose electrons, and undergoes oxidation. Sulphur, and oxygen atoms combine with each other to form a compound or molecule known as sulphate group with the molecular formula of (SO4)\left( {S{O_4}} \right) . Thus, aluminium acts as a cation, when it is involved in the bond formation with sulphate group.
Two aluminium atoms combine with three molecules of sulphate ion forming a compound known as aluminium sulphate with molecular formula of Al2(SO4)3A{l_2}{\left( {S{O_4}} \right)_3}.
The balanced chemical equation of aluminium sulphate dissociation will be as follows:
Al2(SO4)32Al3++3SO42A{l_2}{\left( {S{O_4}} \right)_3} \rightleftharpoons 2A{l^{3 + }} + 3S{O_4}^{2 - }
From the above balanced chemical reaction, one mole of aluminium sulphate produces three moles of sulphate ion.
Thus, the concentration of aluminium sulphate is one third of the concentration of sulphate ion.
Given that the sulfate ion has a concentration of 0.22M0.22M
Thus, concentration of aluminium sulphate will be 13×0.22=0.073M\dfrac{1}{3} \times 0.22 = 0.073M
Thus, when a student found that the sulfate ion concentration in a solution of Al2(SO4)3A{l_2}{\left( {S{O_4}} \right)_3} was 0.22M0.22M then the concentration of Al2(SO4)3A{l_2}{\left( {S{O_4}} \right)_3} in the solution is 0.073M0.073M

Note:
When an ionic compound is formed, the number of electrons lost by an aluminium atom is equal to the number of electrons gained by the sulphate group. Based on this only, the dissociation reaction can be written. The dissociation clearly indicates that aluminium undergoes loss of six electrons, and sulphate group undergoes gain of six electrons.