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Question: A student appears for tests I, II and III. The student is successful if he passes either in tests I ...

A student appears for tests I, II and III. The student is successful if he passes either in tests I and II or tests I and III. The probabilities of the student passing in tests I, II, III are p, q and 12\frac { 1 } { 2 } respectively. If the probability that the student is successful is 12\frac { 1 } { 2 }, then

A

p = 1, q = 0

B

p=23,q=12p = \frac { 2 } { 3 } , q = \frac { 1 } { 2 }

C

There are infinitely many values of p and q

D

All of the above

Answer

There are infinitely many values of p and q

Explanation

Solution

Let A, B and C be the events that the student is successful in test I, II and III respectively, then P (the student is successful)

=P(A)P(B)P(C)+P(A)P(B)P(C)+P(A)P(B)P(C)= P ( A ) \cdot P ( B ) \cdot P \left( C ^ { \prime } \right) + P ( A ) \cdot P \left( B ^ { \prime } \right) \cdot P ( C ) + P ( A ) \cdot P ( B ) \cdot P ( C )

[∵ A, B, C are independent]

=pq(112)+p(1q)(12)+pq(12)=12p(1+q)= p q \left( 1 - \frac { 1 } { 2 } \right) + p ( 1 - q ) \left( \frac { 1 } { 2 } \right) + p q \left( \frac { 1 } { 2 } \right) = \frac { 1 } { 2 } p ( 1 + q )

Ž 12=12p(1+q)\frac { 1 } { 2 } = \frac { 1 } { 2 } p ( 1 + q ) Ž p(1+q)=1p ( 1 + q ) = 1.

This equation has infinitely many values of p and q.