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Question: A string of length L is stretched by L/20 and speed of transverse wave along it is v. The speed of w...

A string of length L is stretched by L/20 and speed of transverse wave along it is v. The speed of wave when it is stretched by L/10 will be: (assume that Hooke's law is applicable) –

A

2v

B

v2\frac{v}{\sqrt{2}}

C

2v\sqrt{2}v

D

4v

Answer

2v\sqrt{2}v

Explanation

Solution

Dl1 = L20\frac{L}{20}, Dl2 = L10\frac{L}{10}

vT\begin{matrix} v \propto \sqrt{T} \end{matrix} and as stress µ strain

T µ Dl

vv=Δ2Δ1\frac { \mathrm { v } ^ { \prime } } { \mathrm { v } } = \sqrt { \frac { \Delta \ell _ { 2 } } { \Delta \ell _ { 1 } } } v=2v\begin{matrix} v' = \sqrt{2}v \end{matrix}